An object has a velocity 0(t) = (3.00 m/s)
+ (1.00 m/s)
at time t = 0.00 s. The acceleration of the object is
(t) = (2.00 m/s3) t
+ (1.00 m/s4) t2
. If the object is located at
0(t) = (1.00 m)
+ (-1.00 m)
at time t = 0.00 s., what is the position of the object at time t = 1.00 s?
A) ( 2.72 m) + ( 6.14 m)
B) ( 4.33 m) + ( 0.0833 m)
C) ( 2.00 m) + ( 1.00 m)
D) ( 5.32 m) + ( 1.34 m)
E) ( 0.333 m) + ( 0.0833 m)
Correct Answer:
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