Find an equation in slope-intercept form (where possible) for the line.
-Through $ (2,1) $, perpendicular to $ -7 x+6 y=-8 $
A) $ y=-\frac{6}{7} x+\frac{19}{7} $
B) $ y=-\frac{6}{7} x $
C) $ y=\frac{6}{7} x-\frac{19}{7} $
D) $ y=-\frac{7}{6} x+19 $

Question

Quizplus · Accepted Answer

The slope of the given line is $\frac{7}{6}$ (after rearranging the equation to slope-intercept form: $y=\frac{7}{6}x+\frac{4}{3}$). The slope of a line perpendicular to this is the negative reciprocal, which is $-\frac{6}{7}$. Using the point (2,1) and the slope $-\frac{6}{7}$, the equation in slope-intercept form is $y=-\frac{6}{7}x+\frac{19}{7}$.

Find an Equation in Slope-Intercept Form (Where Possible) for the Line