Find the nth, or general, term.
-$$\frac { 1 } { 7 } , \frac { 1 } { 49 } , \frac { 1 } { 343 } , \ldots$$
A) $7 ^ { n - 1 }$
B) $\frac { 1 } { 7 ^ { n - 1 } + 6 }$
C) $\frac { 1 } { 7 + 42 ( n - 1 ) }$
D) $\frac { 1 } { 7 ^ { n } }$

Question

Quizplus · Accepted Answer

The sequence is a geometric sequence where each term is obtained by multiplying the previous term by $\frac{1}{7}$. The first term is $\frac{1}{7}$, which can be written as $\frac{1}{7^1}$. The second term is $\frac{1}{49}$, which is $\frac{1}{7^2}$, and so on. Therefore, the nth term is $\frac{1}{7^n}$.

Find the Nth, or General, Term 17,149,1343,…\frac { 1 } { 7 } , \frac { 1 } { 49 } , \frac { 1 } { 343 } , \ldots71​,491​,3431​,…

Find the Nth, or General, Term $\frac { 1 } { 7 } , \frac { 1 } { 49 } , \frac { 1 } { 343 } , \ldots$