Solve.
-$$x ^ { 2 } + 10 x + 25 \leq 0$$
A) $[ 5 , \infty )$
B) $\{ 5 \}$
C) $( - \infty , - 5 ] \cup [ - 5 , \infty )$
D) $\{ - 5 \}$

Name: Solve. -\[x ^ { 2 } + 10 x + 25 \leq 0\] A) $[ 5 , \infty )$ B) $\{ 5 \}$ C) $( - \infty , - 5 ] \cup [ - 5 , \infty )$ D) $\{ - 5 \}$
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Question

Quizplus · Accepted Answer

The given quadratic equation $x^2 + 10x + 25 \leq 0$ can be factored as $(x + 5)^2 \leq 0$. The only value of $x$ that satisfies this equation is $x = -5$, making the solution a single point $\{-5\}$.

Solve - x2+10x+25≤0x ^ { 2 } + 10 x + 25 \leq 0x2+10x+25≤0

Solve
- $x ^ { 2 } + 10 x + 25 \leq 0$