Factor the polynomial f(x). Then solve the equation f(x) = 0.
-$$f ( x ) = x ^ { 3 } + 11 x ^ { 2 } + 36 x + 36$$
A) $( x + 2 ) ( x + 3 ) ( x + 6 ) ; 2,3,6$
B) $( x + 2 ) ( x + 3 ) ( x + 6 ) ; - 2 , - 3 , - 6$
C) $( x - 3 ) ( x - 4 ) ( x - 7 ) ; 3,4,7$
D) $( x + 3 ) ( x + 4 ) ( x + 7 ) ; 3,4,7$

Question

Quizplus · Accepted Answer

To factor the polynomial $f(x) = x^3 + 11x^2 + 36x + 36$, we look for factors of 36 that add up to 11 for the middle term. The correct factorization is $(x + 2)(x + 3)(x + 6)$, which gives the roots $-2, -3, -6$.

Factor the Polynomial F(x) f(x)=x3+11x2+36x+36f ( x ) = x ^ { 3 } + 11 x ^ { 2 } + 36 x + 36f(x)=x3+11x2+36x+36

Factor the Polynomial F(x) $f ( x ) = x ^ { 3 } + 11 x ^ { 2 } + 36 x + 36$