Find the vertex of the parabola.
-$$f ( x ) = 2 x ^ { 2 } - 12 x + 16$$
A) $( - 3,2 )$
B) $( 2 , - 3 )$
C) $( 3 , - 2 )$
D) $( - 2,3 )$

Question

Quizplus · Accepted Answer

The vertex of a parabola in the form $f(x) = ax^2 + bx + c$ can be found using the formula $(- \frac{b}{2a}, f(- \frac{b}{2a}))$. For $f(x) = 2x^2 - 12x + 16$, $a = 2$ and $b = -12$, so the x-coordinate of the vertex is $- \frac{-12}{2*2} = 3$. Plugging $x = 3$ back into the equation gives $f(3) = 2(3)^2 - 12(3) + 16 = 18 - 36 + 16 = -2$, making the vertex $(3, -2)$.

Find the Vertex of the Parabola f(x)=2x2−12x+16f ( x ) = 2 x ^ { 2 } - 12 x + 16f(x)=2x2−12x+16

Find the Vertex of the Parabola $f ( x ) = 2 x ^ { 2 } - 12 x + 16$