Find the zeros of the function. Give exact answers.
-$$f ( x ) = x ^ { 2 } - 9 x + 3$$
A) $\frac { - 9 \pm \sqrt { 69 } \mathrm { i } } { 2 }$
B) $\frac { 9 \pm \sqrt { 69 } } { 2 }$
C) $\frac { 27 \pm \sqrt { 69 } } { 2 }$
D) $\frac { - 9 \pm \sqrt { 69 } } { 4 }$

Question

Quizplus · Accepted Answer

To find the zeros of the function $f(x) = x^2 - 9x + 3$, we use the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 1$, $b = -9$, and $c = 3$. Plugging these values into the formula gives $x = \frac{9 \pm \sqrt{(-9)^2 - 4(1)(3)}}{2(1)} = \frac{9 \pm \sqrt{81 - 12}}{2} = \frac{9 \pm \sqrt{69}}{2}$.

Find the Zeros of the Function f(x)=x2−9x+3f ( x ) = x ^ { 2 } - 9 x + 3f(x)=x2−9x+3

Find the Zeros of the Function $f ( x ) = x ^ { 2 } - 9 x + 3$