Solve the Problem $( S \circ \mathrm { d } ) ( \mathrm { t } ) = 3.21 \mathrm { t }$

Solve the problem.
-Ken is 6 feet tall and is walking away from a streetlight. The streetlight has its light bulb 14 feet above the ground, and Ken is walking at the rate of 1.9 feet per second. Find a function, d(t) , which gives the distance Ken is from the streetlight in terms of time. Find a function, S(d) , which gives the length of Ken's shadow in terms of d. Then find $( S \circ \mathrm { d } ) ( \mathrm { t } ) = 3.21 \mathrm { t }$

A) $( \mathrm { S } \circ \mathrm { d } ) ( \mathrm { t } ) = 1.05 \mathrm { t }$
B) $( \mathrm { S } \circ \mathrm { d } ) ( \mathrm { t } ) = 1.81 \mathrm { t }$
C) $( \mathrm { S } \circ \mathrm { d } ) ( \mathrm { t } ) = 1.43 \mathrm { t }$
D) $( S \circ \mathrm { d } ) ( \mathrm { t } )$