Find an equation of variation for the given situation.
- y varies directly as the square of x , and y=8.75 when x=5 .
A) $y = 0.35 x ^ { 2 }$
B) $y = 0.39 \sqrt { x }$
C) $y = 1.92 x ^ { 2 }$
D) $y = 0.4 x ^ { 2 }$

Question

Find an equation of variation for the given situation.
- y  varies directly as the square of  x , and  y=8.75  when  x=5 .
A) $y = 0.35 x ^ { 2 }$
B) $y = 0.39 \sqrt { x }$
C) $y = 1.92 x ^ { 2 }$
D) $y = 0.4 x ^ { 2 }$

Quizplus · Accepted Answer

Since $y$ varies directly as the square of $x$, the equation of variation is $y = kx^2$. Substituting $y = 8.75$ and $x = 5$ gives $8.75 = k(5)^2$, solving for $k$ gives $k = 0.35$, so the equation is $y = 0.35x^2$.

Find an Equation of Variation for the Given Situation y=0.35x2y = 0.35 x ^ { 2 }y=0.35x2

Find an Equation of Variation for the Given Situation $y = 0.35 x ^ { 2 }$