Interpret the Area under the Standard Normal Curve as a Probability
-Scores on a standardized test are normally distributed with a mean of 100 and a standard deviation of 12 . An individual's test score is found to be 125 . Find the $z$-score corresponding to this value.
A) $2.08$
B) $- 2.08$
C) $0.48$
D) $- 0.48$

Question

Quizplus · Accepted Answer

The $z$-score is calculated using the formula $z = \frac{X - \mu}{\sigma}$, where $X$ is the value in question, $\mu$ is the mean, and $\sigma$ is the standard deviation. For a score of 125, with a mean ($\mu$) of 100 and a standard deviation ($\sigma$) of 12, the $z$-score is $z = \frac{125 - 100}{12} = 2.08$.

Interpret the Area Under the Standard Normal Curve as a Probability