Use the FOIL method to multiply the binomials. Assume any variable exponents represent whole numbers.
-$$\left( 3 x ^ { 3 } - 6 \right) \left( x ^ { 2 } - 5 \right)$$
A) $3 x ^ { 5 } - 21 x ^ { 3 } + 30$
B) $3 x ^ { 5 } - 15 x ^ { 3 } - 6 x ^ { 2 } - 30$
C) $3 x ^ { 5 } - 15 x ^ { 3 } - 6 x ^ { 2 } + 30$
D) $4 x ^ { 5 } - 8 x ^ { 3 } - 7 x ^ { 2 } + 11$

Question

Quizplus · Accepted Answer

Using the FOIL method to multiply the binomials $(3x^3 - 6)$ and $(x^2 - 5)$, we get:First: $3x^3 \cdot x^2 = 3x^{3+2} = 3x^5$,Outer: $3x^3 \cdot (-5) = -15x^3$,Inner: $-6 \cdot x^2 = -6x^2$,Last: $-6 \cdot (-5) = +30$.Adding these together gives $3x^5 - 15x^3 - 6x^2 + 30$.

Use the FOIL Method to Multiply the Binomials (3x3−6)(x2−5)\left( 3 x ^ { 3 } - 6 \right) \left( x ^ { 2 } - 5 \right)(3x3−6)(x2−5)

Use the FOIL Method to Multiply the Binomials $\left( 3 x ^ { 3 } - 6 \right) \left( x ^ { 2 } - 5 \right)$