Solve the problem.
-A twin-engined aircraft can fly 672 miles from city A to city B in 3 hours with the wind and make the return trip in 7 hours against the wind. What is the speed of the wind?
A) 96 mph
B) 48 mph
C) 80 mph
D) 64 mph

Question

Quizplus · Accepted Answer

The speed of the plane in still air is 224 mph (672 miles / 3 hours). The speed against the wind is 96 mph (672 miles / 7 hours). The wind speed is the difference between these two speeds: 224 mph - 96 mph = 128 mph. However, this is incorrect. The correct calculation should be: Let the speed of the plane in still air be x mph and the wind speed be y mph. Then, x + y = 224 and x - y = 96. Solving these equations simultaneously gives y = 64 mph.

Solve the Problem. -A Twin-Engined Aircraft Can Fly 672 Miles from City a from City