Write the first four terms of the sequence.
-$$a _ { n } = \frac { 3 n + 1 } { 3 n }$$
A) $\frac { 7 } { 3 } , \frac { 10 } { 3 } , \frac { 13 } { 3 } , \frac { 16 } { 3 }$
B) $\frac { 4 } { 3 } , \frac { 7 } { 3 } , \frac { 10 } { 7 } , \frac { 13 } { 3 }$
C) $\frac { 4 } { 3 } , \frac { 7 } { 6 } , \frac { 10 } { 9 } , \frac { 13 } { 12 }$
D) $\frac { 7 } { 6 } , \frac { 10 } { 9 } , \frac { 13 } { 12 } , \frac { 16 } { 15 }$

Question

Quizplus · Accepted Answer

The sequence is given by $a_n = \frac{3n + 1}{3n}$. Plugging in $n = 1, 2, 3, 4$, we get the terms $\frac{4}{3}, \frac{7}{6}, \frac{10}{9}, \frac{13}{12}$.

Write the First Four Terms of the Sequence an=3n+13na _ { n } = \frac { 3 n + 1 } { 3 n }an​=3n3n+1​

Write the First Four Terms of the Sequence $a _ { n } = \frac { 3 n + 1 } { 3 n }$