Solve the problem.
-Four bacteria are placed in a petri dish. The population will triple every day. The formula for the number of bacteria in the dish on day t $$N ( t ) = 4 ( 3 ) ^ { t }$$ , where t is the number of days after the four bacteria are placed in the dish. How many bacteria are in the dish six days after the four bacteria are placed in the dish?
A)864
B)72
C)13
D)2916

Question

Quizplus · Accepted Answer

To find the number of bacteria in the dish six days after the initial placement, substitute $t = 6$ into the given formula: $N(6) = 4(3)^6$. Calculating $3^6 = 729$, then multiplying by 4 gives $N(6) = 2916$.

Solve the Problem N(t)=4(3)tN ( t ) = 4 ( 3 ) ^ { t }N(t)=4(3)t

Solve the Problem $N ( t ) = 4 ( 3 ) ^ { t }$