Solve the problem.
-$$P ( t ) = \frac { 980 } { 1 + 20.78 e ^ { - 0.346 t } }$$ The logistic growth model represents the population of a bacterium in a culture tube after t hours. When will the amount of bacteria be 610?
A)7.4 hr
B)4.43 hr
C)1.62 hr
D)10.21 hr

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The Answer of Solve the problem.
-$$P ( t ) = \frac { 980 } { 1 + 20.78 e ^ { - 0.346 t } }$$ The logistic growth model represents the population of a bacterium in a culture tube after t hours. When will the amount of bacteria be 610?
A)7.4 hr
B)4.43 hr
C)1.62 hr
D)10.21 hr

Solve the Problem P(t)=9801+20.78e−0.346tP ( t ) = \frac { 980 } { 1 + 20.78 e ^ { - 0.346 t } }P(t)=1+20.78e−0.346t980​

Solve the Problem $P ( t ) = \frac { 980 } { 1 + 20.78 e ^ { - 0.346 t } }$