Solve the problem.
-A projectile is fired from a cliff 200 feet above the water at an inclination of $45 ^ { \circ }$ to the horizontal, with a muzzle velocity of 380 feet per second. The height h of the projectile above the water is given by h $( x ) = \frac { - 32 x ^ { 2 } } { ( 380 ) ^ { 2 } } + x + 200$, where $x$ is the horizontal distance of the projectile from the base of the cliff. Find the maximum height of the projectile.
A)2256.25 ft
B)3584.38 ft
C)1128.13 ft
D)1328.13 ft

Question

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The Answer of Solve the problem.
-A projectile is fired from a cliff 200 feet above the water at an inclination of $45 ^ { \circ }$ to the horizontal, with a muzzle velocity of 380 feet per second. The height h of the projectile above the water is given by h $( x ) = \frac { - 32 x ^ { 2 } } { ( 380 ) ^ { 2 } } + x + 200$, where $x$ is the horizontal distance of the projectile from the base of the cliff. Find the maximum height of the projectile.
A)2256.25 ft
B)3584.38 ft
C)1128.13 ft
D)1328.13 ft

Solve the Problem 45∘45 ^ { \circ }45∘ To the Horizontal, with a Muzzle Velocity of 380 Feet

Solve the Problem $45 ^ { \circ }$ To the Horizontal, with a Muzzle Velocity of 380 Feet