Solve the polynomial equation in the complex numbers.
-$3 x ^ { 4 } - 22 x ^ { 3 } + 64 x ^ { 2 } - 58 x + 13 = 0$
A) $\left\{ 1 , \frac { 1 } { 3 } , 3 + 2 i , 3 - 2 i \right\}$
B) $\left\{ 1 , - \frac { 1 } { 3 } , 2 + 3 \mathrm { i } , 2 - 3 \mathrm { i } \right\}$
C) $\left\{ - 1 , - \frac { 1 } { 3 } , 2 + 3 i , 2 - 3 i \right\}$
D) $\left\{ - 1 , \frac { 1 } { 3 } , 3 + 2 i , 3 - 2 i \right\}$

Question

Quizplus · Accepted Answer

The polynomial can be factored into $(x-1)(3x-1)(x^2-6x+13)$, which gives the roots $1, \frac{1}{3}, 3+2i, 3-2i$.

Solve the Polynomial Equation in the Complex Numbers 3x4−22x3+64x2−58x+13=03 x ^ { 4 } - 22 x ^ { 3 } + 64 x ^ { 2 } - 58 x + 13 = 03x4−22x3+64x2−58x+13=0

Solve the Polynomial Equation in the Complex Numbers $3 x ^ { 4 } - 22 x ^ { 3 } + 64 x ^ { 2 } - 58 x + 13 = 0$