The function f is one-to-one. Find its inverse.
-$$f ( x ) = \frac { 6 x + 5 } { 7 }$$
A) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 7 \mathrm { x } - 5 } { 6 }$
B) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 7 } { 6 x - 5 }$
C) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 7 x + 5 } { 6 }$
D) $\mathrm { f } ^ { - 1 } ( \mathrm { x } ) = \frac { 7 } { 6 x + 5 }$

Question

Quizplus · Accepted Answer

To find the inverse of the function $f(x) = \frac{6x + 5}{7}$, you swap $x$ and $y$ and solve for $y$. This gives $x = \frac{6y + 5}{7}$, which when solved for $y$ gives $y = \frac{7x - 5}{6}$, which is option A.

The Function F Is One-To-One f(x)=6x+57f ( x ) = \frac { 6 x + 5 } { 7 }f(x)=76x+5​

The Function F Is One-To-One $f ( x ) = \frac { 6 x + 5 } { 7 }$