Find the equation of the line described, and express your answer in the specified form.
-Perpendicular to the line y = -3x - 4; passes through the point (4, 3); slope-intercept form
A) $y = - \frac { 1 } { 3 } x + \frac { 5 } { 3 }$
B) $y = 3 x + \frac { 5 } { 3 }$
C) $y = - 3 x + \frac { 5 } { 3 }$
D) $y = \frac { 1 } { 3 } x + \frac { 5 } { 3 }$

Question

Find the equation of the line described, and express your answer in the specified form.
-Perpendicular to the line y = -3x - 4; passes through the point (4, 3); slope-intercept form 
A) $y = - \frac { 1 } { 3 } x + \frac { 5 } { 3 }$
B) $y = 3 x + \frac { 5 } { 3 }$
C) $y = - 3 x + \frac { 5 } { 3 }$
D) $y = \frac { 1 } { 3 } x + \frac { 5 } { 3 }$

Quizplus · Accepted Answer

The slope of the line perpendicular to $y = -3x - 4$ is the negative reciprocal of -3, which is $\frac{1}{3}$. Using the point-slope form with the point (4, 3), we find the equation of the line to be $y = \frac{1}{3}x + \frac{5}{3}$.

Find the Equation of the Line Described, and Express Your y=−13x+53y = - \frac { 1 } { 3 } x + \frac { 5 } { 3 }y=−31​x+35​

Find the Equation of the Line Described, and Express Your $y = - \frac { 1 } { 3 } x + \frac { 5 } { 3 }$