Solve the radical equation.
-$$\sqrt { 8 x + 33 } = x$$
A) $\left\{ - \frac { 33 } { 7 } \right\}$
B) $\{ 11 \}$
C) $\{ - 3,11 \}$
D) no real solution

Question

Quizplus · Accepted Answer

Squaring both sides gives $8x + 33 = x^2$. Rearranging gives $x^2 - 8x - 33 = 0$. Solving this quadratic equation gives roots $x = 11$ and $x = -3$. Checking these in the original equation, only $x = 11$ satisfies it.

Solve the Radical Equation 8x+33=x\sqrt { 8 x + 33 } = x8x+33​=x

Solve the Radical Equation $\sqrt { 8 x + 33 } = x$