Derive the following result "algebraically" using the properties listed in Theorem 6.2.2. Give
a reason for every step that exactly justiﬁes what was done in the step. $\text { For all sets } A , B \text {, and } C , ( A \cup C ) - B = ( A - B ) \cup ( C - B ) \text {. }$

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The Answer of Derive the following result "algebraically" using the properties listed in Theorem 6.2.2. Give
a reason for every step that exactly justiﬁes what was done in the step. $\text { For all sets } A , B \text {, and } C , ( A \cup C ) - B = ( A - B ) \cup ( C - B ) \text {. }$

Derive the Following Result "Algebraically" Using the Properties Listed in Theorem