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The  str =12+20(\sqrt { \text { str } } = 12 + 20 (

Question 3

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The  str =12+20(\sqrt { \text { str } } = 12 + 20 ( dia ) ) can be used to predict the breaking strength of a rope (in pounds) from its diameter (in inches) . According to this model, how much force should a rope onehalf inch in diameter be able to withstand?


A) 16lbs16 \mathrm { lbs }
B) 22lbs22 \mathrm { lbs }
C) 4.7lbs4.7 \mathrm { lbs }
D) 256lbs256 \mathrm { lbs }
E) 484lbs484 \mathrm { lbs }

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