Write out the sum. Do not evaluate.
-$\sum _ { k = 1 } ^ { 4 } \left( k ^ { 2 } - 4 k - 3 \right)$
A) $- 6 - 7 - 6 - 3 + \ldots$
B) $- 6 - 7 - 6 - 3$
C) $- 6 + 7 - 6 + 3$
D) $1 - 6 - 7 - 6$

Question

Quizplus · Accepted Answer

The sum is evaluated by substituting $k = 1, 2, 3, 4$ into the expression $k^2 - 4k - 3$ and adding the results. For $k = 1$, the expression is $1^2 - 4(1) - 3 = -6$. For $k = 2$, it is $2^2 - 4(2) - 3 = -7$. For $k = 3$, it is $3^2 - 4(3) - 3 = -6$. For $k = 4$, it is $4^2 - 4(4) - 3 = -3$. Therefore, the sum is $-6 - 7 - 6 - 3$.

Write Out the Sum ∑k=14(k2−4k−3)\sum _ { k = 1 } ^ { 4 } \left( k ^ { 2 } - 4 k - 3 \right)∑k=14​(k2−4k−3)

Write Out the Sum $\sum _ { k = 1 } ^ { 4 } \left( k ^ { 2 } - 4 k - 3 \right)$