Determine algebraically whether the function is even, odd, or neither.
-$$f ( x ) = \frac { 1 } { x ^ { 2 } }$$
A) even
B) odd
C) neither

Name: Determine algebraically whether the function is even, odd, or neither. -\[f ( x ) = \frac { 1 } { x ^ { 2 } }\] A) even B) odd C) neither
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Question

Quizplus · Accepted Answer

A function is even if $f(x) = f(-x)$ for all $x$ in the function's domain. For $f(x) = \frac{1}{x^2}$, substituting $-x$ for $x$ gives $f(-x) = \frac{1}{(-x)^2} = \frac{1}{x^2} = f(x)$, which means the function is even.

Determine Algebraically Whether the Function Is Even, Odd, or Neither f(x)=1x2f ( x ) = \frac { 1 } { x ^ { 2 } }f(x)=x21​

Determine Algebraically Whether the Function Is Even, Odd, or Neither $f ( x ) = \frac { 1 } { x ^ { 2 } }$