Solve the problem.
-A rocket is shot straight up in the air from the ground at a rate of 62 feet per second. The rocket is tracked by a range finder that is 450 feet from the launch pad. Let d represent the distance from the rocket to the range finder
And t represent the time, in seconds, since "blastoff". Express d as a function of t.
A) $\mathrm { d } ( \mathrm { t } ) = 450 + 62 \mathrm { t } ^ { 2 }$
B) $d ( t ) = 450 ^ { 2 } + ( 62 t ) ^ { 2 }$
C) $d ( t ) = \sqrt { 62 ^ { 2 } + ( 450 t ) ^ { 2 } }$
D) $d ( t ) = \sqrt { 450 ^ { 2 } + ( 62 t ) ^ { 2 } }$

Question

Solve the problem.
-A rocket is shot straight up in the air from the ground at a rate of 62 feet per second. The rocket is tracked by a range finder that is 450 feet from the launch pad. Let d represent the distance from the rocket to the range finder
And t represent the time, in seconds, since "blastoff". Express d as a function of t. 
A) $\mathrm { d } ( \mathrm { t } ) = 450 + 62 \mathrm { t } ^ { 2 }$
B) $d ( t ) = 450 ^ { 2 } + ( 62 t ) ^ { 2 }$
C) $d ( t ) = \sqrt { 62 ^ { 2 } + ( 450 t ) ^ { 2 } }$
D) $d ( t ) = \sqrt { 450 ^ { 2 } + ( 62 t ) ^ { 2 } }$

Quizplus · Accepted Answer

The distance from the rocket to the range finder can be found using the Pythagorean theorem, where the vertical distance the rocket has traveled is $62t$ and the horizontal distance to the range finder is 450 feet.

Solve the Problem d(t)=450+62t2\mathrm { d } ( \mathrm { t } ) = 450 + 62 \mathrm { t } ^ { 2 }d(t)=450+62t2

Solve the Problem $\mathrm { d } ( \mathrm { t } ) = 450 + 62 \mathrm { t } ^ { 2 }$