Suppose that$f ( n )$ satisfies the divide-and-conquer recurrence relation $f ( n ) = 3 f ( n / 4 ) + n ^ { 2 } / 8 \text { with } f ( 1 ) = 2$ What is $f ( 64 )$ ?

Question

Suppose that$f ( n )$  satisfies the divide-and-conquer recurrence relation $f ( n ) = 3 f ( n / 4 ) + n ^ { 2 } / 8 \text { with } f ( 1 ) = 2$ What is $f ( 64 )$ ?

Quizplus · Accepted Answer

The Answer of Suppose that$f ( n )$  satisfies the divide-and-conquer recurrence relation $f ( n ) = 3 f ( n / 4 ) + n ^ { 2 } / 8 \text { with } f ( 1 ) = 2$ What is $f ( 64 )$ ?

Suppose That f(n)f ( n )f(n) Satisfies the Divide-And-Conquer Recurrence Relation f(n)=3f(n/4)+n2/8 with f(1)=2f ( n ) = 3 f ( n / 4 ) + n ^ { 2 } / 8 \text { with } f ( 1 ) = 2f(n)=3f(n/4)+n2/8 with f(1)=2

Suppose That $f ( n )$ Satisfies the Divide-And-Conquer Recurrence Relation $f ( n ) = 3 f ( n / 4 ) + n ^ { 2 } / 8 \text { with } f ( 1 ) = 2$