Determine which of the following equations is correct.
-$\frac { 1 } { \sin x } \int \sin x d x =$
A) $1 / \sin x + C$
B) $- \cot x + C$
C) $\cos x + C$
D) $\sin x + C$

Name: Determine which of the following equations is correct. -$\frac { 1 } { \sin x } \int \sin x d x =$ A) $1 / \sin x + C$ B) $- \cot x + C$ C) $\cos x + C$ D) $\sin x + C$
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Question

Quizplus · Accepted Answer

The integral of $\sin x$ is $-\cos x$. Therefore, $\frac{1}{\sin x} \int \sin x dx = \frac{1}{\sin x}(-\cos x) = -\cot x + C$.

Determine Which of the Following Equations Is Correct 1sin⁡x∫sin⁡xdx=\frac { 1 } { \sin x } \int \sin x d x =sinx1​∫sinxdx=

Determine Which of the Following Equations Is Correct $\frac { 1 } { \sin x } \int \sin x d x =$