Evaluate the integral by using a substitution prior to integration by parts.
-$$\int x \sqrt { 2 - x } d x$$
A) $\frac { 2 } { 3 } x ( 2 - x ) ^ { 3 / 2 } + \frac { 4 } { 15 } ( 2 - x ) ^ { 5 / 2 } + C$
B) $- \frac { 2 } { 3 } x ( 2 - x ) ^ { 3 / 2 } - \frac { 4 } { 15 } ( 2 - x ) ^ { 5 / 2 } + C$
C) $- \frac { 2 } { 3 } x ( 2 - x ) ^ { 3 / 2 } - \frac { 2 } { 5 } ( 2 - x ) ^ { 5 / 2 } + C$
D) $- \frac { 2 } { 3 } x ( 2 - x ) ^ { 3 / 2 } + \frac { 4 } { 15 } ( 2 - x ) ^ { 5 / 2 } + C$

Question

Quizplus · Accepted Answer

The Answer of Evaluate the integral by using a substitution prior to integration by parts.
-$$\int x \sqrt { 2 - x } d x$$
A) $\frac { 2 } { 3 } x ( 2 - x ) ^ { 3 / 2 } + \frac { 4 } { 15 } ( 2 - x ) ^ { 5 / 2 } + C$
B) $- \frac { 2 } { 3 } x ( 2 - x ) ^ { 3 / 2 } - \frac { 4 } { 15 } ( 2 - x ) ^ { 5 / 2 } + C$
C) $- \frac { 2 } { 3 } x ( 2 - x ) ^ { 3 / 2 } - \frac { 2 } { 5 } ( 2 - x ) ^ { 5 / 2 } + C$
D) $- \frac { 2 } { 3 } x ( 2 - x ) ^ { 3 / 2 } + \frac { 4 } { 15 } ( 2 - x ) ^ { 5 / 2 } + C$

Evaluate the Integral by Using a Substitution Prior to Integration ∫x2−xdx\int x \sqrt { 2 - x } d x∫x2−x​dx

Evaluate the Integral by Using a Substitution Prior to Integration $\int x \sqrt { 2 - x } d x$