Expand the quotient by partial fractions.
-$$\frac { 5 x + 3 } { ( x - 3 ) ( x - 1 ) }$$
A) $\frac { 9 } { x - 3 } + \frac { - 4 } { ( x - 3 ) ( x - 1 ) }$
B) $\frac { 9 } { x - 3 } + \frac { - 4 } { x - 1 }$
C) $\frac { 18 } { x - 3 } + \frac { 8 } { x - 1 }$
D) $\frac { 9 } { x - 3 } + \frac { 4 } { x - 1 }$

Question

Quizplus · Accepted Answer

The partial fraction decomposition of $\frac { 5 x + 3 } { ( x - 3 ) ( x - 1 ) }$ is $\frac { A } { x - 3 } + \frac { B } { x - 1 }$. Solving for A and B, we find $A = 9$ and $B = -4$, leading to $\frac { 9 } { x - 3 } + \frac { - 4 } { x - 1 }$.

Expand the Quotient by Partial Fractions 5x+3(x−3)(x−1)\frac { 5 x + 3 } { ( x - 3 ) ( x - 1 ) }(x−3)(x−1)5x+3​

Expand the Quotient by Partial Fractions $\frac { 5 x + 3 } { ( x - 3 ) ( x - 1 ) }$