Solve the problem.
-Consider the area of the region in the first quadrant enclosed by the curve $y = \frac { 1 } { 8 } \cosh 8 x$, the coordinate axes, and the line $x = 6$. This area is the same as the area of a rectangle of a length s, where $s$ is the length of the curve from $x = 0$ to $x = 6$. What is the height of the rectangle?
A) $\frac { 1 } { 8 }$
B) $\sinh 48$
C) $\frac { 1 } { 64 } \sinh 48$
D) 8

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The Answer of Solve the problem.
-Consider the area of the region in the first quadrant enclosed by the curve $y = \frac { 1 } { 8 } \cosh 8 x$, the coordinate axes, and the line $x = 6$. This area is the same as the area of a rectangle of a length s, where $s$ is the length of the curve from $x = 0$ to $x = 6$. What is the height of the rectangle?
A) $\frac { 1 } { 8 }$
B) $\sinh 48$
C) $\frac { 1 } { 64 } \sinh 48$
D) 8

Solve the Problem y=18cosh⁡8xy = \frac { 1 } { 8 } \cosh 8 xy=81​cosh8x

Solve the Problem $y = \frac { 1 } { 8 } \cosh 8 x$