Find the absolute extreme values of the function on the interval.
-$$f ( x ) = e ^ { x } - x , - 4 \leq x \leq 2$$
A) Minimum value is 1 at $x = 0$; maximum value is $\mathrm { e } ^ { - 4 } + 4$ at $x = - 4$
B) Minimum value is 1 at $x = 0$; no maximum value
C) Minimum value is 1 at $x = 0$; maximum value is $\mathrm { e } ^ { 2 } - 2$ at $\mathrm { x } = 2$
D) Minimum value is $\mathrm { e } ^ { - 4 } + 4$ at $\mathrm { x } = - 4$; maximum value is $\mathrm { e } ^ { 2 } - 2$ at $\mathrm { x } = 2$

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The Answer of Find the absolute extreme values of the function on the interval.
-$$f ( x ) = e ^ { x } - x , - 4 \leq x \leq 2$$
A) Minimum value is 1 at $x = 0$; maximum value is $\mathrm { e } ^ { - 4 } + 4$ at $x = - 4$
B) Minimum value is 1 at $x = 0$; no maximum value
C) Minimum value is 1 at $x = 0$; maximum value is $\mathrm { e } ^ { 2 } - 2$ at $\mathrm { x } = 2$
D) Minimum value is $\mathrm { e } ^ { - 4 } + 4$ at $\mathrm { x } = - 4$; maximum value is $\mathrm { e } ^ { 2 } - 2$ at $\mathrm { x } = 2$

Find the Absolute Extreme Values of the Function on the Interval