L'Hopital's rule does not help with the given limit. Find the limit some other way.
-$\lim _ { x \rightarrow \theta ^ { + } } \frac { 1 } { \cot x \sin x }$
A) 0
B) $\infty$
C) $- 1$
D) 1

Question

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The Answer of L'Hopital's rule does not help with the given limit. Find the limit some other way.
-$\lim _ { x \rightarrow \theta ^ { + } } \frac { 1 } { \cot x \sin x }$
A) 0
B) $\infty$
C) $- 1$
D) 1

L'Hopital's Rule Does Not Help with the Given Limit lim⁡x→θ+1cot⁡xsin⁡x\lim _ { x \rightarrow \theta ^ { + } } \frac { 1 } { \cot x \sin x }limx→θ+​cotxsinx1​

L'Hopital's Rule Does Not Help with the Given Limit $\lim _ { x \rightarrow \theta ^ { + } } \frac { 1 } { \cot x \sin x }$