Find a value of c that makes the function continuous at the given value of x. If it is impossible, state this.
-$f ( x ) = \left\{ \begin{array} { c l }
\frac { - 3 x + 15 } { x - 5 } , & x \neq 5 \
c , & x = 5
\end{array} ; x = 5 \right.$
A) 3
B) -3
C) 15
D) Impossible

Question

Find a value of c that makes the function continuous at the given value of x. If it is impossible, state this.
-$f ( x ) = \left\{ \begin{array} { c l } 
\frac { - 3 x + 15 } { x - 5 } , & x \neq 5 \
c , & x = 5
\end{array} ; x = 5 \right.$
A) 3
B) -3
C) 15
D) Impossible

Quizplus · Accepted Answer

The Answer of Find a value of c that makes the function continuous at the given value of x. If it is impossible, state this.
-$f ( x ) = \left\{ \begin{array} { c l } 
\frac { - 3 x + 15 } { x - 5 } , & x \neq 5 \
c , & x = 5
\end{array} ; x = 5 \right.$
A) 3
B) -3
C) 15
D) Impossible

Find a Value of C That Makes the Function Continuous f(x)={−3x+15x−5,x≠5c,x=5;x=5f ( x ) = \left\{ \begin{array} { c l } \frac { - 3 x + 15 } { x - 5 } , & x \neq 5 \\c , & x = 5\end{array} ; x = 5 \right.f(x)={x−5−3x+15​,c,​x=5x=5​;x=5

Find a Value of C That Makes the Function Continuous $f ( x ) = \left\{ \begin{array} { c l } \frac { - 3 x + 15 } { x - 5 } , & x \neq 5 \\c , & x = 5\end{array} ; x = 5 \right.$