Find the most general antiderivative.
-$$\int \left( \frac { 3 } { x ^ { 2 } + 1 } - \frac { 4 } { x } \right) d x$$
A) $3 \tan ^ { - 1 } x + 4 \ln | x | + C$
B) $3 \tan ^ { - 1 } x - \ln | x | + C$
C) $\frac { \tan ^ { - 1 } x } { 3 } - \frac { \ln | x | } { 4 } + C$
D) $3 \tan ^ { - 1 } x - 4 \ln | x | + C$

Question

Quizplus · Accepted Answer

Use the basic antiderivative rules to get 
$$\int \left( \frac { 3 } { x ^ { 2 } + 1 } - \frac { 4 } { x } \right) d x = 3 \tan ^ { - 1 } x - 4 \ln | x | + C$$
Make sure to include the absolute value around $x$. Choice D matches this result exactly.

Find the Most General Antiderivative ∫(3x2+1−4x)dx\int \left( \frac { 3 } { x ^ { 2 } + 1 } - \frac { 4 } { x } \right) d x∫(x2+13​−x4​)dx

Find the Most General Antiderivative $\int \left( \frac { 3 } { x ^ { 2 } + 1 } - \frac { 4 } { x } \right) d x$