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Solve the Problem g(x,y,z)g ( x , y , z )

Question 128

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Solve the problem.
-For some inexact differential forms df, a function g(x,y,z)g ( x , y , z ) can be found such that dh =g(x,y,z)df= g ( x , y , z ) d f is exact. When it exists, the function g(x,y,z)g ( x , y , z ) is called an "integrating factor". Show that g(x,y,z)=yzxg ( x , y , z ) = \frac { y z } { x } is an integrating factor for the inexact differential df=1xdx+1ydy+1zdz\mathrm { df } = - \frac { 1 } { \mathrm { x } } \mathrm { dx } + \frac { 1 } { \mathrm { y } } \mathrm { dy } + \frac { 1 } { \mathrm { z } } \mathrm { dz } .

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To show that g ( x , y , z ) = \frac { y...

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