$$\text { Set up the iterated integral for evaluating } \iint _ { D } \int f ( r , \theta , z ) d z r d r d \theta \text { over the given region D. }$$

$$\text { Set up the iterated integral for evaluating } \iint _ { D } \int f ( r , \theta , z ) d z r d r d \theta \text { over the given region D. }$$
- $\mathrm { D }$ is the right circular cylinder whose base is the circle $\mathrm { r } = 6 \cos \theta$ in the $x y - p l a n e$ and whose top lies in the plane $z = 8 - x - y$ .

A) $\int _ { 0 } ^ { 2 \pi } \int _ { 0 } ^ { 6 \sin \theta } \int _ { 0 } ^ { 8 - \sin \theta - \cos \theta } f ( r , \theta , z ) d z r d r d \theta$
B) $\int _ { 0 } ^ { 2 \pi } \int _ { 0 } ^ { 6 \cos \theta } \int _ { 0 } ^ { 8 - r ( \cos \theta + \sin \theta ) } \mathrm { f } ( \mathrm { r } , \theta , \mathrm { z } ) \mathrm { dz } \mathrm { rdr } \mathrm { d } \theta$
C) $\int _ { 0 } ^ { \pi } \int _ { 0 } ^ { 6 \cos \theta } \int _ { 0 } ^ { 8 - r ( \cos \theta + \sin \theta ) } f ( r , \theta , z ) d z r d r d \theta$
D) $\int _ { 0 } ^ { \pi } \int _ { 0 } ^ { 6 \sin \theta } \int _ { 0 } ^ { 8 - \sin \theta - \cos \theta } \mathrm { f } ( \mathrm { r } , \theta , \mathrm { z } ) \mathrm { dz } \mathrm { rdr } \mathrm { d } \theta$