Use the given transformation to evaluate the integral.
-$$\begin{array} { l }
u = y - x , v = y + x \
\quad \iint \cos \left( \frac { y - x } { y + x } \right) d x d y ,
\end{array}$$
where $R$ is the trapezoid with vertices at $( 3,0 ) , ( 10,0 ) , ( 0,3 ) , ( 0,10 )$
A) $\frac { 91 } { 4 } \sin 2$
B) $\frac { 91 } { 2 } \sin 2$
C) $\frac { 91 } { 4 } \sin 1$
D) $\frac { 91 } { 2 } \sin 1$

Question

Use the given transformation to evaluate the integral.
-$$\begin{array} { l } 
u = y - x , v = y + x \
\quad \iint \cos \left( \frac { y - x } { y + x } \right) d x d y ,
\end{array}$$
where $R$ is the trapezoid with vertices at $( 3,0 ) , ( 10,0 ) , ( 0,3 ) , ( 0,10 )$
A) $\frac { 91 } { 4 } \sin 2$
B) $\frac { 91 } { 2 } \sin 2$
C) $\frac { 91 } { 4 } \sin 1$
D) $\frac { 91 } { 2 } \sin 1$

Quizplus · Accepted Answer

The Answer of Use the given transformation to evaluate the integral.
-$$\begin{array} { l } 
u = y - x , v = y + x \
\quad \iint \cos \left( \frac { y - x } { y + x } \right) d x d y ,
\end{array}$$
where $R$ is the trapezoid with vertices at $( 3,0 ) , ( 10,0 ) , ( 0,3 ) , ( 0,10 )$
A) $\frac { 91 } { 4 } \sin 2$
B) $\frac { 91 } { 2 } \sin 2$
C) $\frac { 91 } { 4 } \sin 1$
D) $\frac { 91 } { 2 } \sin 1$

Use the Given Transformation to Evaluate the Integral u=y−x,v=y+x∬cos⁡(y−xy+x)dxdy,\begin{array} { l } u = y - x , v = y + x \\\quad \iint \cos \left( \frac { y - x } { y + x } \right) d x d y ,\end{array}u=y−x,v=y+x∬cos(y+xy−x​)dxdy,​

Use the Given Transformation to Evaluate the Integral $\begin{array} { l } u = y - x , v = y + x \\\quad \iint \cos \left( \frac { y - x } { y + x } \right) d x d y ,\end{array}$