The vector r(t) is the position vector of a particle at time t. Find the angle between the velocity and the acceleration vectors at time t = 0.
-$$\mathbf { r } ( \mathrm { t } ) = \sqrt { 3 } \mathrm { ti } + \left( \mathrm { t } + \frac { \pi } { 3 } \mathrm { t } ^ { 2 } \right) \mathbf { k }$$
A) $\frac { \pi } { 2 }$
B) 0
C) $\frac { \pi } { 3 }$
D) $\pi$

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The Answer of The vector r(t) is the position vector of a particle at time t. Find the angle between the velocity and the acceleration vectors at time t = 0.
-$$\mathbf { r } ( \mathrm { t } ) = \sqrt { 3 } \mathrm { ti } + \left( \mathrm { t } + \frac { \pi } { 3 } \mathrm { t } ^ { 2 } \right) \mathbf { k }$$
A) $\frac { \pi } { 2 }$
B) 0
C) $\frac { \pi } { 3 }$
D) $\pi$

The Vector R(t) Is the Position Vector of a Particle r(t)=3ti+(t+π3t2)k\mathbf { r } ( \mathrm { t } ) = \sqrt { 3 } \mathrm { ti } + \left( \mathrm { t } + \frac { \pi } { 3 } \mathrm { t } ^ { 2 } \right) \mathbf { k }r(t)=3​ti+(t+3π​t2)k

The Vector R(t) Is the Position Vector of a Particle $\mathbf { r } ( \mathrm { t } ) = \sqrt { 3 } \mathrm { ti } + \left( \mathrm { t } + \frac { \pi } { 3 } \mathrm { t } ^ { 2 } \right) \mathbf { k }$