Provide an appropriate response.
-$\text { Prove that if } \mathbf { v } \text { and } \mathbf { u } \text { are differentiable functions of } t \text {, then } \frac { \mathrm { d } } { \mathrm { dt } } ( \mathbf { u } + \mathbf { v } ) = \frac { \mathrm { d } \mathbf { u } } { \mathrm { dt } } + \frac { \mathrm { d } \mathbf { v } } { \mathrm { dt } } \text {. }$

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The Answer of Provide an appropriate response.
-$\text { Prove that if } \mathbf { v } \text { and } \mathbf { u } \text { are differentiable functions of } t \text {, then } \frac { \mathrm { d } } { \mathrm { dt } } ( \mathbf { u } + \mathbf { v } ) = \frac { \mathrm { d } \mathbf { u } } { \mathrm { dt } } + \frac { \mathrm { d } \mathbf { v } } { \mathrm { dt } } \text {. }$

Provide an Appropriate Response