Solved

Provide an Appropriate Response 3.23.2 Feet Above the Ground 152ft/sec152 \mathrm { ft } / \mathrm { sec }

Question 64

Multiple Choice

Provide an appropriate response.
-A baseball is hit when it is 3.23.2 feet above the ground. It leaves the bat with an initial speed of 152ft/sec152 \mathrm { ft } / \mathrm { sec } , making an angle of 1818 ^ { \circ } with the horizontal. Assuming a drag coefficient k=0.12\mathrm { k } = 0.12 , how high does the ball go, and when dc it reach maximum height? For projectiles with linear drag:
x=x0+v0k(1ekt) cosαy=y0+v0k(1ekt) sinα+gk2(1ktekt) \begin{array} { l } x = x _ { 0 } + \frac { v _ { 0 } } { k } \left( 1 - e ^ { - k t } \right) \cos \alpha \\y = y _ { 0 } + \frac { v _ { 0 } } { k } \left( 1 - e ^ { - k t } \right) \sin \alpha + \frac { g } { k ^ { 2 } } \left( 1 - k t - e ^ { - k t } \right) \end{array}
where k\mathrm { k } is the drag coefficient, v0\mathrm { v } _ { 0 } and α\alpha are the projectile's initial speed and launch angle, and gg is the acceleratic of gravity (32ft/sec2) \left( 32 \mathrm { ft } / \sec ^ { 2 } \right) .


A) Maximum height = 3.48 feet;
B) Maximum height = 0.21 feet; time to maximum height = 0.05 sec time to maximum height = -0.21 sec
C) Maximum height = 3.51 feet;
D) Maximum height = 8.71 feet; time to maximum height = 0.02 sec time to maximum height = 0.74 sec

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents