Find the center and radius of the sphere.
-$$x ^ { 2 } + ( y + 10 ) ^ { 2 } + ( z - 1 ) ^ { 2 } = 64$$
A) C(0, 10, -1), a = 64
B) C(0, -10, 1), a = 64
C) C(0, 10, -1), a = 8
D) C(0, -10, 1), a = 8

Question

Quizplus · Accepted Answer

The equation of a sphere in standard form is $(x - h)^2 + (y - k)^2 + (z - l)^2 = r^2$, where $(h, k, l)$ is the center of the sphere and $r$ is the radius. Comparing this with the given equation, we find the center to be $C(0, -10, 1)$ and the radius $r = \sqrt{64} = 8$.

Find the Center and Radius of the Sphere x2+(y+10)2+(z−1)2=64x ^ { 2 } + ( y + 10 ) ^ { 2 } + ( z - 1 ) ^ { 2 } = 64x2+(y+10)2+(z−1)2=64

Find the Center and Radius of the Sphere $x ^ { 2 } + ( y + 10 ) ^ { 2 } + ( z - 1 ) ^ { 2 } = 64$