Solve the problem.
-A bullet is fired with a muzzle velocity of $1324 \mathrm { ft } / \mathrm { sec }$ from a gun aimed at an angle of $36 ^ { \circ }$ above the horizontal. Find the horizontal component of the velocity.
A) 1071 ft/sec
B) 961.9 ft/sec
C) 778.2 ft/sec
D) -169.4 ft/sec

Question

Quizplus · Accepted Answer

The horizontal component of the velocity can be found using the formula $v_x = v \cos(\theta)$, where $v = 1324 \, \text{ft/sec}$ is the muzzle velocity and $\theta = 36^\circ$ is the angle. Thus, $v_x = 1324 \cos(36^\circ) \approx 1071 \, \text{ft/sec}$.

Solve the Problem 1324ft/sec1324 \mathrm { ft } / \mathrm { sec }1324ft/sec

Solve the Problem $1324 \mathrm { ft } / \mathrm { sec }$