Find an equation for the line tangent to the curve at the point defined by the given value of t.
-$$x = 10 t ^ { 2 } - 7 , y = t ^ { 3 } , t = 1$$
A) $y = \frac { 3 } { 20 } x - \frac { 11 } { 20 }$
B) $y = \frac { 3 } { 10 } x + 1$
C) $y = \frac { 20 } { 3 } x - \frac { 11 } { 20 }$
D) $y = \frac { 3 } { 20 } x + \frac { 11 } { 20 }$

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The Answer of Find an equation for the line tangent to the curve at the point defined by the given value of t.
-$$x = 10 t ^ { 2 } - 7 , y = t ^ { 3 } , t = 1$$
A) $y = \frac { 3 } { 20 } x - \frac { 11 } { 20 }$
B) $y = \frac { 3 } { 10 } x + 1$
C) $y = \frac { 20 } { 3 } x - \frac { 11 } { 20 }$
D) $y = \frac { 3 } { 20 } x + \frac { 11 } { 20 }$

Find an Equation for the Line Tangent to the Curve x=10t2−7,y=t3,t=1x = 10 t ^ { 2 } - 7 , y = t ^ { 3 } , t = 1x=10t2−7,y=t3,t=1

Find an Equation for the Line Tangent to the Curve $x = 10 t ^ { 2 } - 7 , y = t ^ { 3 } , t = 1$