$$\text { Find the value of } d ^ { 2 } y / d x ^ { 2 } \text { at the point defined by the given value of } t \text {. }$$
-$$x = \sqrt { t + 3 } , y = - t , t = 46$$
A) $- 2$
B) $\frac { 1 } { 7 }$
C) 14
D) $- \frac { 1 } { 2 }$

Question

Quizplus · Accepted Answer

Explanation:Given $$x = \sqrt { t + 3 } , y = - t$$$$\frac { dy } { dx } = \frac { \frac { d } { dt } [ - t ] } { \frac { d } { dt } [ \sqrt { t + 3 } ] } = \frac { - 1 } { \frac { 1 } { 2 \sqrt { t + 3 } } } = - 2 \sqrt { t + 3 }$$$$\frac { d ^ { 2 } y } { d x ^ { 2 } } = \frac { \frac { d } { dt } [ - 2 \sqrt { t + 3 } ] } { \frac { d } { dt } [ \sqrt { t + 3 } ] } = \frac { - 2 \cdot \frac { 1 } { 2 \sqrt { t + 3 } } } { \frac { 1 } { 2 \sqrt { t + 3 } } } = - 2$$At $t = 46$,$$\frac { d ^ { 2 } y } { d x ^ { 2 } } = - 2$$

Find the value of d2y/dx2 at the point defined by the given value of t. \text { Find the value of } d ^ { 2 } y / d x ^ { 2 } \text { at the point defined by the given value of } t \text {. } Find the value of d2y/dx2 at the point defined by the given value of t.

$\text { Find the value of } d ^ { 2 } y / d x ^ { 2 } \text { at the point defined by the given value of } t \text {. }$