Find the area of the specified region.
-Shared by the circles $r = 3$ and $r = 6 \sin \theta$
A) $\frac { 3 } { 2 } ( 2 \pi + 3 \sqrt { 3 } )$
B) $3 \pi$
C) $\frac { 9 } { 2 } \pi$
D) $\frac { 3 } { 2 } ( 4 \pi - 3 \sqrt { 3 } )$

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The Answer of Find the area of the specified region.
-Shared by the circles $r = 3$ and $r = 6 \sin \theta$
A) $\frac { 3 } { 2 } ( 2 \pi + 3 \sqrt { 3 } )$
B) $3 \pi$
C) $\frac { 9 } { 2 } \pi$
D) $\frac { 3 } { 2 } ( 4 \pi - 3 \sqrt { 3 } )$

Find the Area of the Specified Region r=3r = 3r=3 And r=6sin⁡θr = 6 \sin \thetar=6sinθ

Find the Area of the Specified Region $r = 3$ And $r = 6 \sin \theta$