Graph.
-$16 x^{2}-9 y^{2}=144$

Question

Quizplus · Accepted Answer

The given equation represents a hyperbola with center at the origin, horizontal transverse axis, and vertices at (+/-6,0). The distance between the center and vertices can be found using the formula c = sqrt(a^2 + b^2), where a and b are the lengths of the semi-major and semi-minor axes, respectively. In this case, a = 4 and b = 3, so c = 5. Therefore, the foci are located at (+/-5,0). The graph should look like a sideways "U" shape with asymptotes passing through the center in the form of y = +/- (3/4)x. Only option C accurately represents these features.

Graph - 16x2−9y2=14416 x^{2}-9 y^{2}=14416x2−9y2=144 A) B) C) D)

Graph
- $16 x^{2}-9 y^{2}=144$ A)

B)

C)

D)