Solved

Model Applied Situations with Matrix Operations
The \perp Shape in the Figure Below Is Shown Using 9 Pixels

Question 83

Multiple Choice

Model Applied Situations with Matrix Operations
The \perp shape in the figure below is shown using 9 pixels in a 3×33 \times 3 grid. The color levels are given to the right of the figure. Use the matrix [131131333]\left[ \begin{array} { l l l } 1 & 3 & 1 \\ 1 & 3 & 1 \\ 3 & 3 & 3 \end{array} \right] that represents a digital photograph of the \perp shape to solve the problem.  Model Applied Situations with Matrix Operations  The  \perp  shape in the figure below is shown using 9 pixels in a  3 \times 3  grid. The color levels are given to the right of the figure. Use the matrix  \left[ \begin{array} { l l l } 1 & 3 & 1 \\ 1 & 3 & 1 \\ 3 & 3 & 3 \end{array} \right]  that represents a digital photograph of the  \perp  shape to solve the problem.   -Adjust the contrast by changing the black to light grey and the light grey to black. Use matrix addition to accomplish this.  A)   \left[ \begin{array} { l l l } 1 & 3 & 1 \\ 1 & 3 & 1 \\ 3 & 3 & 3 \end{array} \right] + \left[ \begin{array} { r r r } 2 & - 2 & 2 \\ 2 & - 2 & 2 \\ - 2 & - 2 & - 2 \end{array} \right] = \left[ \begin{array} { l l l } 3 & 1 & 3 \\ 3 & 1 & 3 \\ 1 & 1 & 1 \end{array} \right]  B)   \left[ \begin{array} { l l l }  1 & 3 & 1 \\ 1 & 3 & 1 \\ 3 & 3 & 3 \end{array} \right] + \left[ \begin{array} { l l l }  - 2 & - 2 & - 2 \\ - 2 & - 2 & - 2 \\ - 2 & - 2 & - 2 \end{array} \right] = \left[ \begin{array} { l l l }  3 & 1 & 3 \\ 3 & 1 & 3 \\ 1 & 1 & 1 \end{array} \right]  C)   \left[ \begin{array} { l l l }  1 & 3 & 1 \\ 1 & 3 & 1 \\ 3 & 3 & 3 \end{array} \right] + \left[ \begin{array} { r r r }  1 & - 1 & 1 \\ 1 & - 1 & 1 \\ - 1 & - 1 & - 1 \end{array} \right] = \left[ \begin{array} { l l l }  3 & 1 & 3 \\ 3 & 1 & 3 \\ 1 & 1 & 1 \end{array} \right]  D)   \left[ \begin{array} { l l l }  1 & 3 & 1 \\ 1 & 3 & 1 \\ 3 & 3 & 3 \end{array} \right] + \left[ \begin{array} { l l l }  2 & 2 & 2 \\ 2 & 2 & 2 \\ 2 & 2 & 2 \end{array} \right] = \left[ \begin{array} { l l l }  3 & 1 & 3 \\ 3 & 1 & 3 \\ 1 & 1 & 1 \end{array} \right]
-Adjust the contrast by changing the black to light grey and the light grey to black. Use matrix addition to accomplish this.


A) [131131333]+[222222222]=[313313111]\left[ \begin{array} { l l l } 1 & 3 & 1 \\ 1 & 3 & 1 \\ 3 & 3 & 3 \end{array} \right] + \left[ \begin{array} { r r r } 2 & - 2 & 2 \\ 2 & - 2 & 2 \\ - 2 & - 2 & - 2 \end{array} \right] = \left[ \begin{array} { l l l } 3 & 1 & 3 \\ 3 & 1 & 3 \\ 1 & 1 & 1 \end{array} \right]
B)
[131131333]+[222222222]=[313313111]\left[ \begin{array} { l l l } 1 & 3 & 1 \\1 & 3 & 1 \\3 & 3 & 3\end{array} \right] + \left[ \begin{array} { l l l } - 2 & - 2 & - 2 \\- 2 & - 2 & - 2 \\- 2 & - 2 & - 2\end{array} \right] = \left[ \begin{array} { l l l } 3 & 1 & 3 \\3 & 1 & 3 \\1 & 1 & 1\end{array} \right]
C)
[131131333]+[111111111]=[313313111]\left[ \begin{array} { l l l } 1 & 3 & 1 \\1 & 3 & 1 \\3 & 3 & 3\end{array} \right] + \left[ \begin{array} { r r r } 1 & - 1 & 1 \\1 & - 1 & 1 \\- 1 & - 1 & - 1\end{array} \right] = \left[ \begin{array} { l l l } 3 & 1 & 3 \\3 & 1 & 3 \\1 & 1 & 1\end{array} \right]
D)
[131131333]+[222222222]=[313313111]\left[ \begin{array} { l l l } 1 & 3 & 1 \\1 & 3 & 1 \\3 & 3 & 3\end{array} \right] + \left[ \begin{array} { l l l } 2 & 2 & 2 \\2 & 2 & 2 \\2 & 2 & 2\end{array} \right] = \left[ \begin{array} { l l l } 3 & 1 & 3 \\3 & 1 & 3 \\1 & 1 & 1\end{array} \right]

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents