Solve the problem.
-A sample of $300 \mathrm {~g}$ of lead-210 decays to polonium-210 according to the function given by $\mathrm { A } ( \mathrm { t } ) = 300 \mathrm { e } ^ { - 0.032 \mathrm { t } }$, where $\mathrm { t }$ is time in years. What is the amount of the sample after 60 years (to the nearest g)?
A) $44 \mathrm {~g}$
B) $2046 \mathrm {~g}$
C) $230 \mathrm {~g}$
D) $32 \mathrm {~g}$

Question

Quizplus · Accepted Answer

To find the amount of the sample after 60 years, substitute $t = 60$ into the given function: $A(60) = 300e^{-0.032(60)}$. Calculating this gives approximately $44 \mathrm {~g}$.

Solve the Problem 300 g300 \mathrm {~g}300 g Of Lead-210 Decays to Polonium-210 According to the Function Given

Solve the Problem $300 \mathrm {~g}$ Of Lead-210 Decays to Polonium-210 According to the Function Given