Solve the problem.
-Use the mathematical model for power gain, $G = \log \left( \frac { P _ { 0 } } { P _ { i } } \right) ^ { 10 }$, where $P _ { 0 }$ is the output power in watts and $P _ { i }$ is the input power in watts. Determine the power gain $\mathrm { G }$, in decibels, for an amplifier with an output $P _ { 0 }$ of 19 watts and an input $P _ { i }$ of $1.1$ watts. Round to five decimal places if necessary.
A) $12.37361 \mathrm {~dB}$
B) $12.52853 \mathrm {~dB}$
C) $13.37361 \mathrm {~dB}$
D) $13.20146 \mathrm {~dB}$

Question

Quizplus · Accepted Answer

Using the given formula, we have:
\begin{align*}
G &= \log \left( \frac { P _ { 0 } } { P _ { i } } ight) ^ { 10 }\
&= 10\log \left( \frac {19}{1.1} ight)\
&\approx \boxed{12.37361} 	ext{ dB (rounded to five decimal places)}
\end{align*}

Solve the Problem G=log⁡(P0Pi)10G = \log \left( \frac { P _ { 0 } } { P _ { i } } \right) ^ { 10 }G=log(Pi​P0​​)10

Solve the Problem $G = \log \left( \frac { P _ { 0 } } { P _ { i } } \right) ^ { 10 }$