Solve the problem.
-A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 228 feet of fencing and does not fence the side along the street, what is the largest area that
Can be enclosed?
A) $6498 \mathrm { ft } ^ { 2 }$
B) $12,996 \mathrm { ft } ^ { 2 }$
C) $3249 \mathrm { ft } ^ { 2 }$
D) $9747 \mathrm { ft } ^ { 2 }$

Question

Solve the problem.
-A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 228 feet of fencing and does not fence the side along the street, what is the largest area that
Can be enclosed? 
A) $6498 \mathrm { ft } ^ { 2 }$
B) $12,996 \mathrm { ft } ^ { 2 }$
C) $3249 \mathrm { ft } ^ { 2 }$
D) $9747 \mathrm { ft } ^ { 2 }$

Quizplus · Accepted Answer

The largest area that can be enclosed by a given amount of fencing, when one side is not fenced, is achieved by creating a rectangle where the length is twice the width. The total amount of fencing used for the two widths and one length is 228 feet. Let $w$ be the width, then the length is $2w$, and the perimeter equation is $2w + 2w = 228$, simplifying to $4w = 228$, so $w = 57$ feet. The length is $2w = 114$ feet. The area is $w \times length = 57 \times 114 = 6498 \, \text{ft}^2$.

Solve the Problem 6498ft26498 \mathrm { ft } ^ { 2 }6498ft2

Solve the Problem $6498 \mathrm { ft } ^ { 2 }$